Respuesta :

gmany
[tex]Use:\ y-y_1=m(x-x_1)[/tex]

[tex]We\ have:\\\\m=\dfrac{4}{5}\\\\(-2;\ 1)\to x_1=-2\ and\ y_1=1[/tex]

[tex]Substitute:\\\\y-1=\dfrac{4}{5}(x-(-2))\\\\\boxed{B.\ y-1=\dfrac{4}{5}(x+2)}[/tex]