The given line has slope -2, so the desired line will have a slope that is the negative reciprocal of that:
m = -1/(-2) = 1/2
The point-slope form of the equation of the line can be written as
y = m(x -h) +k
for a line with slope m through point (h, k). For your m=1/2, (h, k) = (6, -2), the equation of your line is
y = (1/2)(x -6) -2
y = (1/2)x -5
The equation of the desired line is ...
y = (1/2)x -5
