Substitute the value of x = 9 to the equations:
[tex]A.\ 3x-7=-34\\\\L_s=3\cdot9-7=27-7=20;\ R_s=-34\\\\L_s\neq R_s\\\\B.\ x-9=1\\\\L_s=9-9=9;\ R_s=1\\\\L_s\neq R_s\\\\C.\ \dfrac{x}{9}-8=9\\\\L_s=\dfrac{9}{9}-8=1-8=-7;\ R_s=9\\\\L_s\neq R_s\\\\D.\ 4x+5=41\\\\L_s=4\cdot9+5=36+5=41;\ R_s=41\\\\L_s=R_s[/tex]
Answer: D. 4x + 5 =41
