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febreezeforease febreezeforease
  • 18-07-2018
  • Mathematics
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The equation of this circle is -


a. (x + 3)^2 + (y – 3)^2 = 9

b. x^2 + y^2 = 3

c. x^2 + y^2 = 9

d. x^2 + y^2 =[tex] \sqrt{3} [/tex]

The equation of this circle is a x 32 y 32 9 b x2 y2 3 c x2 y2 9 d x2 y2 tex sqrt3 tex class=

Respuesta :

Аноним Аноним
  • 18-07-2018

Hello!


The standard equation of a circle is x² + y² = r², when the center is at the origin.


So therefore, we just need to substitute the radius into the equation to find the appropriate equation.


x² + y² = (3)²

x² + y² = 9


Therefore, the equation of the circle is C, x² + y² = 9.

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