consecutive integers have a difference of 1 between them
let the brothers have ages n , n + 1 and n + 2 thus
n + n + 1 + n + 2 = 96
3n + 3 = 96
subtract 3 from both sides of the equation
3n = 96 - 3 = 93
divide both sides by 3
n = [tex]\frac{93}{3}[/tex] = 31
The ages are 31 , 32 and 33
