RoseG012
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Ms.Meyer remarks, "isn't it great? This theater usually charges $9 per student. On Student Night, I can bring 47 more students for the same cost!" How many students can Ms. Meyer bring to the theater?

Tickets: $6

Respuesta :

Let's assume

Ms.Meyer used to bring x students for the cost $9 per student

so, total cost = 9x

now, we are given

For ticket cost $6 , she can brings 47 more students

so, total students =x+47

total cost =6*(x+47)

now, we are given total costs are same for both

we get

[tex]9x=6(x+47)[/tex]

we can solve for x

[tex]9x=6x+282[/tex]

Subtract both sides by 6x

[tex]9x-6x=6x+282-6x[/tex]

[tex]3x=282[/tex]

Divide both sides by 3

[tex]\frac{3x}{3}=\frac{282}{3}[/tex]

[tex]x=94[/tex]

so, Ms. Meyer brings 94 students to theatre.........Answer

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