Respuesta :

y-3=-1(x-2)
y-3 = -x+2
y= -x +5

y = x + 1

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - x + 11 is in this form with slope m = - 1

the slope of a perpendicular line = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-1}[/tex] = 1

y = x + c ← is the partial equation

to find c substitute (2, 3 ) into the partial equation

3 = 2 + c ⇒ c = 3 - 2 = 1

y = x + 1 ← equation in slope-intercept form