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18-11-2018
Mathematics

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Find the difference. (2x^2 - 3x + 7) - (x^2 + 6x - 12)A)

A) x^2 + 3x - 5

B) x^2 - 3x + 19

C) x^2 - 6x + 12

D) x^2 - 9x + 19

Respuesta :

Аноним Аноним

18-11-2018

Its D.

(2x^2 - 3x + 7) - (x^2 + 6x - 12)

Distribute the negative over the second parentheses:-

= (2x^2 - 3x + 7) - x^2 - 6x + 12

= x^2 - 9x + 19 (answer)

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