[tex]8>5-3q\qquad\text{subtract 8 from both sides}\\\\0>-3-3q\qquad\text{add 3q to both sides}\\\\3q>-3\qquad\text{divide both sides by 3}\\\\q>-1\\\\-3q>-13\qquad\text{change the signs}\\\\3q<13\qquad\text{divide both sides by 3}\\\\q<\dfrac{13}{3}\\\\-1 < q < \dfrac{13}{3}\to q\in\left(-1;\ \dfrac{13}{3}\right)[/tex]
