Answer:
It is quadratic.
The constant term is:-12
Step-by-step explanation:
1. You can apply the Distributive Property of multiplication, as following:
[tex]f(x)=(3x-6)(-4x+2)\\f(x)=(3x)(-4x)+(3x)(2)+(-6)(-4x)+(-6)(2)\\f(x)=-12x^{2}+6x+24x-12\\f(x)=12x^{2}+30x-12[/tex]
2. The function has the form:
[tex]f(x)=ax^{2}+bx+c[/tex]
Therefore, it is a quadratic function, where [tex]c[/tex] is the constant term.
3. Therefore, the constant term is -12
