Answer:
The first four terms of the sequence are-6, -2, 2 and 6
Step-by-step explanation:
The given sequence is [tex]a_n=4n-6[/tex]
In order to find the first four term of the sequence we put n =0, 1, 2 and 3.
For n =0
[tex]a_0=4(0)-6=-6[/tex]
For n =1
[tex]a_1=4(1)-6=-2[/tex]
For n =2
[tex]a_2=4(2)-6=2[/tex]
For n =3
[tex]a_3=4(3)-6=6[/tex]
Therefore, the first four terms of the sequence are
-6, -2, 2 and 6
