MarivelisseR1676 MarivelisseR1676
  • 20-02-2019
  • Chemistry
contestada

If 18.9 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentration of the ammonia?

Respuesta :

superman1987
superman1987 superman1987
  • 01-03-2019

Answer:

3.024 M.

Explanation:

  • Based on at the neutralization, the no. of millimoles of acid (HCl) is equal to the no. of millimoles of the base (ammonia).

(MV)HCl = (MV)ammonia

M of HCl = 0.80 M & V of HCl = 18.9 mL.

M of ammonia = ??? M & V of ammonia = 5.0 mL.

∴ M of ammonia = (MV)HCl / V of ammonia = (0.80 M)(18.9 mL) / (5.0 mL) = 3.024 M.

Answer Link

Otras preguntas

how do I figure out the weight loss of tina? she lost 3 pounds on the first week of her diet. she gained a pound on the second week, and then lost 2 pounds a we
y=-3/4x+1 find the slope and y-intercept
Find three consecutive even integers whose sum is 36.
how do you find the least common multiple of these two expressions. 10x^5v^8 and 25x^4v^7u^2
What word describes the relationship between oppsite angles of a parallelogram?
true or false, there is no solution to the systems of inequalities shown belowy<3x+5y>-x+4
Describe how a person can count the rate if beating of the left ventricle.
The perimeter of a square is 20 ft. If you increase the length of the square by 2 feet and decrease the width by 1 foot, what is the area, in square feet, of th
simplify please! find the solution.
a rectangular plot of land is 100 feet long and 50 feet wide how long is the walkway along the diagonal? round to the nearest foot.