21-04-2016
Mathematics

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(√9x^4 y)^-3

Help please

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28-04-2016

remember
√xy=√x times √y
and
x^-m=1/(x^m)

simplify parenthasees firs
(√9x^4y)=√9 times √x^4 times √y=3*x^2*√y=3x^2√y
now we have

(3x^2√y)^-3=1/((3x^2√y)^3)=1/(27x^6y√y)

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