Answer:
[tex]\large\boxed{p=1}[/tex]
Step-by-step explanation:
[tex]\dfrac{2}{5}+p=\dfrac{4}{5}+\dfrac{3}{5}p\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{2}{5\!\!\!\!\diagup_1}+5p=5\!\!\!\!\diagup^1\cdot\dfrac{4}{5\!\!\!\!\diagup_1}+5\!\!\!\!\diagup^1\cdot\dfrac{3}{5\!\!\!\!\diagup_1}p\\\\2+5p=4+3p\qquad\text{subtract 2 from both sides}\\\\5p=2+3p\qquad\text{subtract 3p from both sides}\\\\2p=2\qquad\text{divide both sides by 2}\\\\p=1[/tex]
