Answer:
[tex]x+3y=15[/tex]
Step-by-step explanation:
Formula :- the equation of line which passes through the two points (x1,y1) and (x2,y2)
T-y1/y1-y2=x-x1/x1-x2[/tex]
therefore, the equation of the line which passes through the two points (-6,7) and (-3,6) is
[tex]y1=7,y2=6[/tex]
[tex]x1=-6 ,x2=-3[/tex]
by using above formula
[tex]y-7/7-6=x+6/-6+3[/tex]
[tex]y-7=x+6/-3[/tex]
by cross multiply
[tex]-3y+21=x+6[/tex]
[tex]x+3y=21-6[/tex]
[tex]x+3y=15[/tex]
hence, this is required of line that passes through (-6,7) and (-3,6).
