sheritamcgill2 sheritamcgill2
  • 17-05-2019
  • Mathematics
contestada

The function f(x)=x^2+4.2x+3.6 has an axis of symmetof x=-2-. What is the minimum value of the function

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 17-05-2019

ANSWER

The minimum value is -0.8

EXPLANATION

The given

[tex]f(x)=x^2+4.2x+3.6[/tex]

The minimum value is the y-value of the vertex (minimum point).

To find the minimum value of the function, we substitute x=-2 into the function to get;

[tex]f( - 2)=( - 2)^2+4.2( - 2)+3.6[/tex]

[tex]f( - 2)=4 - 8.4+3.6 = - 0.8[/tex]

The minimum value is -0.8

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