Answer:
see explanation
Step-by-step explanation:
Using the rules of exponents
• [tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex]
• [tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex]
(a)
[tex]27^{\frac{1}{3} }[/tex] = [tex]\sqrt[3]{27}[/tex] = 3
(b)
[tex]25^{-\frac{1}{2} }[/tex]
= [tex]\frac{1}{25^{\frac{1}{2} } }[/tex] = [tex]\frac{1}{\sqrt{25} }[/tex] = [tex]\frac{1}{5}[/tex]
