juniorsmith00017
juniorsmith00017 juniorsmith00017
  • 19-05-2019
  • Mathematics
contestada

What is the cube root of 27a^12

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 19-05-2019

ANSWER

[tex]3{a}^{4 } [/tex]

EXPLANATION

The cube root of

[tex]27 {a}^{12} [/tex]

is

[tex] \sqrt[3]{27 {a}^{12} } [/tex]

This is the same as:

[tex](27 {a}^{12} )^{ \frac{1}{3} } [/tex]

[tex]( {3}^{3} ({a}^{4})^{3} )^{ \frac{1}{3} } [/tex]

[tex] = (3{a}^{4} )^{3 \times \frac{1}{3} } [/tex]

[tex] = 3{a}^{4 } [/tex]

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