thinkerbelly5156 thinkerbelly5156
  • 17-06-2019
  • Chemistry
contestada

The kw for water at 0 °c is 0.12× 10–14 m2. Calculate the ph of a neutral aqueous solution at 0 °c.

Respuesta :

superman1987
superman1987 superman1987
  • 30-06-2019

Answer:

pH = 7.46.

Explanation:

  • The ionization of water is given by the equation :

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq),

  • The equilibrium constant (Kw) expression is:

Kw = [H⁺][OH⁻] = 0.12 x 10⁻¹⁴.  

in pure water and neutral aqueous solution, [H⁺] = [OH⁻]  

So, Kw = [H⁺]²

∴ 0.12 x 10⁻¹⁴ = [H⁺]²

∴ [H⁺] = 3.4 x 10⁻⁸ M.

∵ pH = - log [H⁺]  

pH = - log (3.4 x 10⁻⁸) = 7.46.

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