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How can (1/2)x-5=(1/3)x+6 be set up as a system of equations?
Answers:
A) 2y+x=-10
3y+x=18
B) 2y+2x=-10
3y+3x=18
C) 2y-x=-10
3y-x=18
D) 2y-2x=-10
3y-3x=18

Respuesta :

sqdancefan

Answer:

 C)

  • 2y-x=-10
  • 3y-x=18

Step-by-step explanation:

Set each side of the equation equal to y, then rearrange to standard form.

  (1/2)x -5 = y . . . left side of the equal sign

  x -10 = 2y . . . . multiply by 2

  -10 = 2y -x . . . . subtract x

__

  (1/3)x +6 = y . . . right side of the equal sign

  x +18 = 3y . . . . . multiply by 3

  18 = 3y -x . . . . . subtract x

The corresponding system of equations is ...

  • 2y -x = -10
  • 3y -x = 18

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