prescottjayden2003 prescottjayden2003
  • 17-07-2019
  • Mathematics
contestada

In set-builder notation, how do you write the solutions of 2x − 7 ≥ 11?

Respuesta :

calculista
calculista calculista
  • 28-07-2019

Answer:

{ x ∈ R | x ≥  9 }

Step-by-step explanation:

we have

[tex]2x-7 \geq 11[/tex]

solve for x

Adds 7 both sides

[tex]2x\geq 11+7[/tex]

[tex]2x\geq 18[/tex]

Divide by 2 both sides

[tex]x\geq 18/2[/tex]

[tex]x\geq 9[/tex]

The solution is the interval -----> [9,∞)

In set builder notation

{ x ∈ R | x ≥  9 }

All real numbers greater than or equal to 9

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