Answer:
Step-by-step explanation:
Given
[tex]m^2-n^2[/tex] is even i.e.
it is a multiple of 2
let us suppose it 2k
and we know that it is possible only when either both m&n is odd or even
i.e.
[tex]\left ( even\right )^2-\left ( even\right )^2[/tex]=even number
[tex]\left ( odd\right )^2-\left ( odd\right )^2[/tex]=odd number
thus m-n is even for both case i.e. for both m&n either odd or even
