Answer:
force = 11.33 [tex]kg-m/s^{2}[/tex]
Explanation:
given data:
sled mass = 17.0 kg
inital velocity (U) = 4.10 m/s
elapsed time (T) 6.15 s
final velocity (V) = 0
final momentum P2 = 0
Initial momentum of sledge is
[tex]P_{1}=mU[/tex]
[tex]P_{1}= 17.0 * 4.10 = 69.7 kg- m/s[/tex]
from newton second law of motion
[tex]F=\frac{\Delta P}{\Delta t}[/tex]
[tex]F = \frac{P_{1}-P_{2}}{T}[/tex]
Kgm/s^2
[tex]F = \frac{69.7-0}{6.15}= 11.33[tex]kg-m/s^{2}[/tex][/tex]
