Answer:
[tex]I = 2.4 *10^{-2} A = 2.4 mA[/tex]
Explanation:
The magnetic field B inside long solenoid with current I is given as
[tex]B = \frac{N \mu_o I}{L}[/tex]
where
N is number of turn of solenoids = 1140 turns
[tex]\mu_0 = 4*\pi *10^{-7} T.m[/tex]
I is current that passes through solenoid
L is length along which current pass = 0.350 m
plugging value to get required value of current
[tex]1.00*10^{-4} = \frac{1140*4*\pi *10^{-7} I}{0.350}[/tex]
[tex]I = 2.4 *10^{-2} A = 2.4 mA[/tex]
