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A child uses a rubber band to launch a bottle cap at an angle of 37.0° above the horizontal. The cap travels a horizontal distance of 1.30 m in 1.20 s. What was the initial speed of the bottle cap, just after leaving the rubber band, in m/s

Respuesta :

Answer:

Initial velocity will be 1.356 m/sec      

Explanation:

Let the initial speed = u

Angle at which rubber band is launched = 37°

Horizontal component of initial velocity [tex]u_x=ucos\Theta =ucos37^{\circ}=0.7986u[/tex]

Time is given as t = 1.20 sec

Distance in horizontal direction = 1.30 m

We know that distance = speed × time

So time [tex]t=\frac{distance}{speed}[/tex]

[tex]1.20=\frac{1.3}{0.7986u}[/tex]

[tex]u=1.356m/sec[/tex]

So initial velocity will be 1.356 m/sec

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