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20-05-2016
Mathematics

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What are the solutions for the equation 2z^2+4z+2=0

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apologiabiology apologiabiology

20-05-2016

undistribute 2
2(z^2+2z+1)=0
factor
2(z+1)(z+1)=0
se to zero
2=0 false
z+1=0
z=-1

solution is z=-1

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