Answer:
Explanation:
Given
In R-L-C circuit frequency is very high
Inductive Reactance for inductor is given by [tex]X_L=2\pi f\cdot L[/tex]
Inductive Reactance for Capacitor is given by [tex]X_c=\frac{1}{2\pi f\cdot C}[/tex]
as frequency becomes too high then [tex]X_L[/tex] will become very large and and [tex]X_c [/tex]will be approximately zero .
In other words inductor behave as a very high resistance and Capacitor behaves as very small resistance
