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19-12-2019
Engineering

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Determine the voltage across a 2000 pF capacitor that is storing 20 microcouloms (20 µC) of charge.

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uzairkheshgi488 uzairkheshgi488

20-12-2019

Answer:

V= 10,000 V

Explanation:

Capacitance= C= 2000 pF

Charge = q = 20 μC

Relationship between voltage, charge and capacitance of a capacitor is:

Q= CV

⇒ V = Q/C

⇒ V= 20* [tex]10^{-6}[/tex]/[tex]2000*10^{-12 }[/tex]

⇒ V= 10,000 V

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