Answer:
[tex]$ f(x) = 9 \bigg(\frac{5}{3} \bigg)^x $[/tex]
Step-by-step explanation:
Note the f(0) = 9
and f(1) = 15
Since, f(x) = abˣ substituting for x, we get:
9 = f(0) = a . b⁰ = a
⇒ a = 9
Now, f(1) = 15
⇒ 15 = a . b¹
⇒ 15 = 9 . b
⇒ b = [tex]$ \frac{15}{9} $[/tex]
Therefore, [tex]$ f(x) = 9 . \bigg( \frac{5}{3} \bigg) ^x $[/tex]
Hence, the answer.
