bhagatujjwal9999 bhagatujjwal9999
  • 21-01-2020
  • Physics
contestada

Calculate the specific
heat capacity of substance having mass 5 kg whose
temperature increase from 15°C to 25°C by the supply of
19 KJ​

Respuesta :

ednorobello92 ednorobello92
  • 21-01-2020

Answer: c= 0.38 J/ g °C

Explanation: Use the equation Q= mcΔT and derive to solve for c.

c = Q / mΔT

First convert 19 KJ  to joules

19 kJ x 1000 J / 1 kJ = 19000 J

Then convert 5 kg to grams

5 kg x 1000 g / 1 kg = 5000 g

After that substitute the following variables into the equation.

c= 19000 J / 5000 g ( 25 - 15 ) = 0.38 J/ g°C

Answer Link

Otras preguntas

numbers 20 - 22 please
A businessman has 10 employees. His salary is equal to 6 times the average of employees salaries. If the 11 of them receive a total of $64,000 in one year, what
100 rational numbers can be inserted  between 2 and 7? give your views on this statement
What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge?
A positive charge is placed in an electric field that points west. What direction is the force on the positive particle?
what is 98% as a fraction
The greatest common factor of 3m2n + 12mn2 is
what is 98% as a fraction
what is a personal narrative essay?
what does 'hit the fan' mean?