Answer:
5x
Step-by-step explanation:
Given expression: [tex]\frac{5x^2+20x}{x+4}[/tex]
Take the common number 5 outside in the numerator.
[tex]\frac{5x^2+20x}{x+4}=\frac{5(x^2+4x)}{x+4}[/tex]
Now, take x common in both the terms in numerator.
[tex]\frac{5(x^2+4x)}{x+4}=\frac{5x(x+4)}{x+4}[/tex]
Cancel out the common factor in the both numerator and denominator.
[tex]\frac{5x(x+4)}{x+4}=5x[/tex]
Hence, the answer is 5x.
