Answer: The required probability is 0.25.
Step-by-step explanation:
Since we have given that
Radius of the dartboard = 4 in
Area of the dartboard is given by
[tex]\pi r^2=3.14\times (4)^2=3.14\times 16=50.24\ in^2[/tex]
Radius of the shaded region = 2 in
Area of shaded region is given by
[tex]\pi r^2=3.14\times (2)^2=12.56\ in^2[/tex]
So, the probability that the dart lands in the shaded circular region is given by
[tex]\dfrac{12.56}{50.24}=0.25[/tex]
Hence, the required probability is 0.25.
