Answer:
Explanation:
Given
volume of sample [tex]V_1=90\ mL[/tex]
Temperature [tex]T_1=298\ K[/tex]
Pressure [tex]P_1=702\ mm\ of\ Hg[/tex]
for different conditions
Temperature [tex]T_2=273\ K[/tex]
Pressure [tex]P_2=760\ mm\ of\ Hg[/tex]
suppose [tex]V_2[/tex] is the volume of sample
Using ideal gas equation
[tex]PV=nRT[/tex]
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
[tex]\frac{702\times 90}{298}=\frac{760\times V_2}{273}[/tex]
[tex]V_2=76.15\ mL[/tex]
