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A 0.90-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 4.0 N for a distance of 3.0 m. How much farther would the force have to act for the block to have 61 J of kinetic energy?

Respuesta :

MathPhys

Answer:

12 m

Explanation:

Work = change in energy

W = ΔE

Fd = ΔE

(4.0 N) d = 61 J

d = 15.25 m

Rounded to two significant figures, the distance the force would have to act over is 15 m, which is 12 m more than the 3.0 m it traveled.

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