stormez
stormez stormez
  • 20-02-2020
  • Mathematics
contestada

how do you solve the simultaneous equations ?
y = x + 4
y = 2x² + 3x - 1​

Respuesta :

PollyP52 PollyP52
  • 20-02-2020

Answer:

(1.16, 5.16) and (-2.16, 1.84)    to the nearest hundredth.

Step-by-step explanation:

By substitution. You substitute y = x + 4 into the second equation:

x + 4 = 2x^2 + 3x - 1

2x^2 + 2x - 5 = 0

x = [ -2 +/- sqrt (2^2 - 4*1*-5) ] / 2*2

= -1/2 +/1 sqrt 24/4

= 1.158 , - 2.158

When x =  1.158 , y = 1.158 + 4 = 5.158

When x = -2.158, y = -2.158 + 4 = 1.842.

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