levidonivan202ow691l
levidonivan202ow691l levidonivan202ow691l
  • 21-02-2020
  • Mathematics
contestada

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A B C D class=

Respuesta :

Аноним Аноним
  • 21-02-2020

[tex]n^{16}[/tex] and 9 are the squares of, respectively, [tex]n^8[/tex] and 3.

So, using

[tex]a^2-b^2=(a+b)(a-b)[/tex]

we have

[tex]n^{16}-9=(n^8+3)(n^8-3)[/tex]

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