Answer:
Magnetic field at the mid point of coil is 6.74 x 10⁻³ T
Explanation:
Given :
Current flowing through the solenoid, I = 3.50 A
Length of the solenoid, L = 30 cm = 0.3 m
Number of turns in the solenoid, N = 460
Magnetic field inside the coil at its mid point is given by the relation:
B = μ₀nI ...(1)
So, equation (1) becomes:
[tex]B=\mu_{0}\frac {N}{L}I[/tex]
Substitute the suitable values in the above equation.
[tex]B=4\pi\times10^{-7}\times \frac {460}{0.3}\times3.50[/tex]
B = 6.74 x 10⁻³ T
