Answer:
Effort force is given as 129.3 N
Explanation:
As we know that AMA is the ratio of out force and input force
so here we will have
[tex]AMA = \frac{F_{out}}{F_{in}}[/tex]
here we know that
[tex]F_{out} = 225 N[/tex]
[tex]F_{in} = 1.74[/tex]
now we have
[tex]1.74 = \frac{225}{F_{in}}[/tex]
so we have
[tex]F_{in} = 129.3 N[/tex]
