lukeybrown20 lukeybrown20
  • 20-03-2020
  • Mathematics
contestada

Factorise 14x^2 -x-3

Respuesta :

HisPrincess17 HisPrincess17
  • 20-03-2020

Answer:

Hope this helps :)

Step-by-step explanation:

Factor by grouping

(7x-3)(2x+1)

Answer Link
PollyP52 PollyP52
  • 20-03-2020

Answer:

(2x - 1)(7x + 3).

Step-by-step explanation:

14x^2 -x - 3

Use the 'ac' method.

First multiply the leading coefficient by the last term:

14 * -3 = -42.

Now we need to find 2 numbers whose product is -42 and whose sum is the coefficient of x (which is -1).

They are -7 and  6, so we write:

14x^2 - 7x + 6x - 3          Now factorise this by grouping:

=  7x(2x - 1) + 3(2x - 1)     2x - 1 is common:

= (2x - 1)(7x + 3).

 

Answer Link

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