iloveanime2007 iloveanime2007
  • 20-03-2020
  • Physics
contestada

Charges of −5.3 µC and +5.3 µC are separated by 4.2 cm. Find the electric force between them.

Respuesta :

aristocles aristocles
  • 31-03-2020

Answer:

Force between two charges is given as 143.3 N

Explanation:

As we know that electrostatic force between two point charges is given as

[tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we know that

[tex]q_1 = -5.3 \mu C[/tex]

[tex]q_2 = 5.3 \mu C[/tex]

also we know that

[tex]r = 4.2 cm[/tex]

so we have

[tex]F = \frac{(9\times 10^9)(5.3 \times 10^{-6})(5.3\times 10^{-6})}{0.042^2}[/tex]

so we have

[tex]F = 143.3 N[/tex]

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