mackenziehull99
mackenziehull99 mackenziehull99
  • 16-07-2016
  • Mathematics
contestada

given f(x)= x^4-3x^3+2x^2-7x-11 find all roots to the nearest 0.001

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keeners keeners
  • 16-07-2016
x1= 3.329
x2= 0.291 + 1.882
x3= 0.291 - 1.882
x4= -0.911
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Аноним Аноним
  • 22-08-2019

Answer:

The given function is

   [tex]f(x)= x^4-3x^3+2x^2-7x-11[/tex]

By rational root test, the roots of the polynomial can be

1, -1, 11, and -11.

When you will graph the polynomial, you will find that there are two real roots and two imaginary roots.

By, Graphically two real roots are = 3.329,& -0.911.

These two roots are near to three decimal places.

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