Tiffabritha Tiffabritha

19-07-2016
Mathematics

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4/1 sqrt3-sqrt2 rationalize?

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dalendrk dalendrk

25-07-2016

[tex]\dfrac{4}{\sqrt3-\sqrt2}=\dfrac{4}{\sqrt3-\sqrt2}\cdot\dfrac{\sqrt3+\sqrt2}{\sqrt3+\sqrt2}=\dfrac{4(\sqrt3+\sqrt2)}{(\sqrt3)^2-(\sqrt2)^2}\\\\=\dfrac{4\sqrt3+4\sqrt2}{3-2}=4\sqrt3+4\sqrt2[/tex]

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