We are interested in the dimensions of a certain rectangle. This rectangle has length triple the side of the square and width two units less than the side of the square. If the two areas are equal, what are the rectangle's dimensions (w x h)?

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pinklineja8cowgi pinklineja8cowgi

19-07-2016
Mathematics

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We are interested in the dimensions of a certain rectangle. This rectangle has length triple the side of the square and width two units less than the side of the square. If the two areas are equal, what are the rectangle's dimensions (w x h)?

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meerkat18 meerkat18 · Answer 1 · 2016-07-20T21:07:43+02:00

Let s be the side of the square. The length of the rectangle is 3s and its width is equal to s - 2. From the given condition,
A (square) = A (rectangle)
s² = (3s)(s - 2)
s² = 3s² - 6s
-2s² = -6s
s = 3
Thus, the length of the rectangle is 9 and its width is 1