Given:
In ΔABC, ∠C = 90°, ∠A = 50° and AB = 3 unit.
To find the value of BC.
Formula:
By Trigonometric Ratio we get,
[tex]sin \ \theta=\frac{opposite}{Hypotenuse}[/tex]
Now,
With respect to θ = 50°, AB is the hypotenuse and AB is the opposite side.
So,
[tex]sin \ 50^{\circ}=\frac{BC}{AB}[/tex]
[tex]sin \ 50^{\circ}=\frac{BC}{3}[/tex]
[tex]BC = 3 \times sin 50^{\circ}[/tex]
[tex]BC = 2.298 = 2.3[/tex] (approx)
Hence,
The value of BC is 2.3 units.
