Answer:
The center is at (3,1) and the radius is [tex]\sqrt{8}[/tex]
Step-by-step explanation:
I am going to assume you meant to write
[tex](x-3)^2+(y-1)^2 = 8[/tex]
Since if both variables were x it would not be a circle:
Then you can find the center and radius using the general formula of a circle:
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
where the center is at (h,k) and r is the radius
Therefore:
The center is at (3,1) and the radius is [tex]\sqrt{8}[/tex]
