The required difference is [tex]\frac{12x^3-1-6x}{2x^2}[/tex]
The given expression is,
[tex]6x-\frac{1}{2x^2} -\frac{3}{x}[/tex]
Taking LCM [tex]2x^2[/tex]
[tex]6x-\frac{1}{2x^2} -\frac{3}{x} =\frac{12x^3-1-6x}{2x^2}[/tex]
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