jay58651
jay58651 jay58651
  • 20-06-2020
  • Mathematics
contestada

Find the value of x for which the graph of y = 3x^2 - 8x + 7 achieves its minimum y-value.​

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abidemiokin
abidemiokin abidemiokin
  • 26-06-2020

Answer:

The y value achieves its minimum at x = 4/3

Step-by-step explanation:

Given the graph of y to be 3x² - 8x + 7, to get the value of x for which the graph function achieves its minimum y value, we need to find its turning point first.

At the turning point, dy/dx = 0

Given y = 3x² - 8x + 7

[tex]\frac{dy}{dx} = 6x-8\\ at\ turning\ point\ 6x-8 = 0[/tex]

[tex]6x = 8\\x = \frac{8}{6}\\ x =\frac{4}{3}[/tex]

The y value achieves its minimum at x = 4/3

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