Answer:
Option B
Step-by-step explanation:
Area of kite = product of 2 diagonals, p and q / 2
here, p = 10 + 10 = 30 feet
q = 3 + 3 = 6 feet
∴ Area = 30 × 6 / 2
90 ft^2
Hope it helps
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[tex]\boxed{Area = 90 ft^2}[/tex]
Diagonal 1 = p = 3+3 = 6 ft
Diagonal 2 = q = 10+20 = 30 ft
Area = [tex]\frac{pq}{2}[/tex]
Area = [tex]\frac{(6)(30)}{2}[/tex]
Area = 3*30
Area = 90 ft^2
