darshandevnani2007
darshandevnani2007 darshandevnani2007
  • 18-07-2020
  • Mathematics
contestada

the number 144 is multiplied with 2^-3 , 12^-1 and 3^-2 consecutively . Find the final product pls quick :)

Respuesta :

Alfpfeu
Alfpfeu Alfpfeu
  • 18-07-2020

Answer:

[tex]\boxed{\sf \ \ \ \dfrac{1}{6} \ \ \ }[/tex]

Step-by-step explanation:

Hello

when you multiply by [tex]2^{-3}[/tex]

it is equivalent to divide by [tex]2^3[/tex]

so we are looking for

[tex]144*2^{-3}*12^{-1}*3^{-2}=\dfrac{144}{2^3*12*3^2}=\dfrac{9*16}{2^3*12*3^2}\\=\dfrac{3^2*2^4}{2^3*12*3^2}=\dfrac{2}{12}=\dfrac{1}{6}[/tex]

hope this helps

do not hesitate if you have any question

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