Answer:
49 m/s
Explanation:
This is the question from the document:
1. A bag dropped from a helicopter falls with an acceleration of 9.8m/s2. What is its velocity after 5s?
We can find the answer by using the equation a = (v-u) / t
Acceleration a = 9.81m/s2
initial velocity u = 0 m/s (the bag is only dropped, so there's no initial velocity already existing)
time t= 5s
final velocity v = unknown
9.8 = (v -0) / 5
v - 0 = 9.8x5
v = 49 m/s
